`x`is a positive integer prove that f(

`x`) =

`x`

^{2}+

`x`+ 1 will never divide by 5.

2. Consider the expression

`x`+ 1, where

^{x}`x`be a positive integer.

It can be verified that

`x`= 7 is the least value for which

`x`+ 1 divides by 2

^{x}^{3}.

Given that

`n`is a positive integer, find the least value of

`x`for which

`x`+ 1 is divisible by 2

^{x}^{n}.

## No comments:

Post a Comment